请教关于图片的x.y坐标偏移量.

Tempo

数张连续动作的图片大小不同,如果都按照x=100和y=100的坐标来画的话产生的动作会移位,请教各位你们是怎么处理图片间的坐标偏移的?
假设图片的坐标偏移量是未知的,可以求出吗?

nogood

在你做图片时就要把图片的偏移X，Y 写出来.

nogood

在你做图片时就要把图片的偏移X，Y 写出来.

------------------------------------------------------------------

"001681.bmp",28,70,0,0
"001682.bmp",28,66,28,0
"001683.bmp",28,66,56,0
"001684.bmp",28,70,84,0
"001685.bmp",28,66,112,0
"001686.bmp",28,66,140,0
"001691.bmp",36,66,168,0
"001692.bmp",24,64,204,0
"001693.bmp",28,68,228,0
"001694.bmp",32,68,256,0
"001695.bmp",28,66,288,0
"001696.bmp",24,64,316,0
"001701.bmp",40,64,340,0
"001702.bmp",24,66,380,0
"001703.bmp",20,66,404,0
"001704.bmp",40,64,424,0
"001705.bmp",24,64,464,0
"001706.bmp",20,66,488,0
"001711.bmp",32,70,0,72
"001712.bmp",28,68,32,72
"001713.bmp",24,66,60,72
"001714.bmp",36,66,84,72
"001715.bmp",24,64,120,72
"001716.bmp",28,68,144,72
"001721.bmp",28,72,172,72
"001722.bmp",28,68,200,72
"001723.bmp",28,68,228,72
"001724.bmp",28,72,256,72
"001725.bmp",28,68,284,72
"001726.bmp",28,70,312,72
"001731.bmp",36,66,340,72
"001732.bmp",24,64,376,72
"001733.bmp",28,68,400,72
"001734.bmp",32,70,428,72
"001735.bmp",28,68,460,72
"001736.bmp",24,66,488,72
"001741.bmp",40,64,0,144
"001742.bmp",24,64,40,144
"001743.bmp",20,66,64,144
"001744.bmp",40,64,84,144
"001745.bmp",24,66,124,144
"001746.bmp",20,66,148,144
"001751.bmp",32,68,168,144
"001752.bmp",28,66,200,144
"001753.bmp",24,64,228,144
"001754.bmp",36,66,252,144
"001755.bmp",24,66,288,144
"001756.bmp",28,68,312,144

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[em7] [em4] [em3] [em20]

Tempo

我想这位兄弟理解错我的意思了.我所说的不是如何在一整张图片里找某一小块图的坐标偏移.我的意思是问在屏幕上画图片的坐标偏移.

就像下面那张图,如果都按照x=100 y=100的位置来画的话,第三张很明显会移位.要x=x+x偏移量和y=y+y偏移量才能得到正确的显示位置.我现在的问题就是这个偏移量有办法得到吗?

dengguoyu

一样的方法嘛，你定义每幅画在那个偏移量显示不就行了 @@
最好你在画图时调整画面，使每幅子图的中心重合并保持大小一致，这是最方便最高效的方法

Tempo

图片不是我做的,是从游戏里截取出来的.而且每张图片的偏移量并不相同.大小也不相同.那个偏移是不可以自己随便定的.

我给出一套动作.恳请哪位高手能做个示范.谢谢了.

Tempo

附件2

dengguoyu

调整一下，花不了多少时间的
或者不要以左上角作原点，试试以右下角或中心作原点来画