在计算插值的时候，求余为什么要加1啊

绿豆饼

suppose you want to move an object from one point to another over a period of 1,000 milliseconds. The following code (processed once per frame) will accomplish this, continuously looping back from the end to the start of the path in an endless cycle.

// vecPoints[2] = path's starting and ending coordinate vectors
// Every frame, use the following code to position an object
// along the straight path based on the current time.
float Scalar = (float)(timeGetTime() % 1001) / 1000.0f;

/*上面的timeGetTime求余为什么要加1啊,我认为直接要1000就可以了？？！*/

D3DXVECTOR3 vecPos = (vecPoints[1] − vecPoints[0]) *Scalar + vecPoints[0];
// Use vecPos.x, vecPos.y, and vecPos.z coordinates for object

茹枫

是不是想要0~1000?

绿豆饼

明白了，谢谢楼上的提醒