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Option Explicit
Private Declare Function MapVirtualKey Lib "user32" Alias "MapVirtualKeyA" (ByVal wCode As Long, ByVal wMapType As Long) As Long
Private Declare Function SendMessage Lib "user32" Alias "SendMessageA" (ByVal hwnd As Long, ByVal wMsg As Long, ByVal wParam As Long, lParam As Any) As Long
Private Declare Function FindWindow Lib "user32" Alias "FindWindowA" (ByVal lpClassName As String, ByVal lpWindowName As String) As Long
Private Declare Function FindWindowEx Lib "user32" Alias "FindWindowExA" (ByVal hWnd1 As Long, ByVal hWnd2 As Long, ByVal lpsz1 As String, ByVal lpsz2 As String) As Long
Private Const WM_KEYDOWN = &H100
Private Const WM_KEYUP = &H101
Private Declare Function PostMessage Lib "user32" Alias " ostMessageA" (ByVal hwnd As Long, ByVal wMsg As Long, ByVal wParam As Long, ByVal lParam As Long) As Long
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Private Sub Command1_Click()
Dim jsb As Long
jsb = FindWindow("red stone- the lunatic story", vbNullString)'可以把vbnullstring改为你需要的
Dim mhwnd As Long
mhwnd = FindWindowEx(jsb, 0, "edit", vbNullString)
Dim lParam As Long
lParam = makelparam(vbKey5, False)
PostMessage mhwnd, WM_KEYDOWN, vbKey5, lParam
lParam = makelparam(vbKey5, True)
PostMessage mhwnd, WM_KEYUP, vbKey5, lParam
End Sub
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'请高手帮我看下上面的按键,这段代码的有什么地方不对
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Private Function makelparam(ByVal VirtualKey As Long, ByVal flag As Boolean) As Long
Dim s As String
Dim Firstbyte As String 'lparam参数的24-31位
If flag = False Then 'keydown
Firstbyte = "00"
Else
Firstbyte = "C0" 'keyup
End If
Dim Scancode As Long
'获得虚拟键扫描码
Scancode = MapVirtualKey(VirtualKey, 0)
Dim Secondbyte As String 'lparam参数的16-23位,即虚拟键扫描码
Secondbyte = Right("00" & Hex(Scancode), 2)
s = Firstbyte & Secondbyte & "0001" '0001为lparam参数的0-15位,即发送次数
makelparam = Val("&H" & s)
End Function
最好看看整段的代码有有什么地方不对 这个用到记事本个好使 在游戏里就不好使
请教高手!!!!!!!!!!!!!!!!!!!!!!!!!!
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