矩阵求逆函数实现,继续扫盲

ricohcanon

顶啦

dai_zeng

//检验原矩阵的有效性     if(fabs(a._44 - 1.0f) > 0.001f)         return false;     if(fabs(a._14)>0.001f || fabs(a._24)>0.001f || fabs(a._34)>0.001f)         return false;


为什么是a._44？a是什么？source?

ricohcanon

LS，a._44是矩阵a第四行第四列的元素，a是一个四阶矩阵。

Devil

a 是 source, 写的时候错掉了。

xgreenclover

This matrix inverse algorithm assume that the fourth column of the matrix is[0 0 0 1].

The matrix generated by applying inversable transformation on identity matrix is always inversable.
In 3D games, most of us just use three kinds of inversable matrix transformation: translation, rotation and scale.of course, you can also use other kinds of inversable transformation.
So we needn't worry about that the matrix is uninversable in most times.

小小C

求逆在《3D游戏的数学方法》中讲得很清楚

chloe

corpus: Re:矩阵求逆函数实现,继续扫盲

不可逆咋办？

求广义逆